Write a C program to check leap year

• The program first declares a variable year to store the user input.
• It then prompts the user to enter a year using the printf() and scanf() functions.
• An if-else statement is used to check whether year is a leap year or not. According to the Gregorian calendar, a year is a leap year if it is divisible by 4, but not by 100, unless it is divisible by 400. The if condition checks whether year is divisible by 4 but not by 100, or whether year is divisible by 400. If the condition is true, the program prints that year is a leap year. Otherwise, the program prints that year is not a leap year.
• Finally, the program returns 0 to indicate successful execution.

#include <stdio.h>

int main() {
    int year;

    printf("Enter a year: ");
    scanf("%d", &year);

    if ((year % 4 == 0 && year % 100 != 0) || year % 400 == 0) {
        printf("%d is a leap year.", year);
    } else {
        printf("%d is not a leap year.", year);
    }

    return 0;
}

OUTPUT

Enter a year: 2024
2024 is a leap year.